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119 lines
3.7 KiB
119 lines
3.7 KiB
2 years ago
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import { isTag, hasChildren } from "domhandler";
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/**
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* Search a node and its children for nodes passing a test function.
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*
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* @category Querying
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* @param test Function to test nodes on.
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* @param node Node to search. Will be included in the result set if it matches.
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* @param recurse Also consider child nodes.
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* @param limit Maximum number of nodes to return.
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* @returns All nodes passing `test`.
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*/
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export function filter(test, node, recurse = true, limit = Infinity) {
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if (!Array.isArray(node))
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node = [node];
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return find(test, node, recurse, limit);
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}
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/**
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* Search an array of node and its children for nodes passing a test function.
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*
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* @category Querying
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* @param test Function to test nodes on.
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* @param nodes Array of nodes to search.
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* @param recurse Also consider child nodes.
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* @param limit Maximum number of nodes to return.
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* @returns All nodes passing `test`.
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*/
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export function find(test, nodes, recurse, limit) {
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const result = [];
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for (const elem of nodes) {
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if (test(elem)) {
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result.push(elem);
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if (--limit <= 0)
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break;
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}
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if (recurse && hasChildren(elem) && elem.children.length > 0) {
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const children = find(test, elem.children, recurse, limit);
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result.push(...children);
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limit -= children.length;
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if (limit <= 0)
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break;
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}
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}
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return result;
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}
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/**
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* Finds the first element inside of an array that matches a test function.
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*
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* @category Querying
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* @param test Function to test nodes on.
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* @param nodes Array of nodes to search.
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* @returns The first node in the array that passes `test`.
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* @deprecated Use `Array.prototype.find` directly.
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*/
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export function findOneChild(test, nodes) {
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return nodes.find(test);
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}
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/**
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* Finds one element in a tree that passes a test.
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*
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* @category Querying
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* @param test Function to test nodes on.
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* @param nodes Array of nodes to search.
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* @param recurse Also consider child nodes.
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* @returns The first child node that passes `test`.
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*/
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export function findOne(test, nodes, recurse = true) {
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let elem = null;
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for (let i = 0; i < nodes.length && !elem; i++) {
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const checked = nodes[i];
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if (!isTag(checked)) {
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continue;
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}
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else if (test(checked)) {
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elem = checked;
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}
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else if (recurse && checked.children.length > 0) {
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elem = findOne(test, checked.children, true);
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}
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}
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return elem;
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}
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/**
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* @category Querying
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* @param test Function to test nodes on.
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* @param nodes Array of nodes to search.
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* @returns Whether a tree of nodes contains at least one node passing the test.
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*/
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export function existsOne(test, nodes) {
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return nodes.some((checked) => isTag(checked) &&
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(test(checked) ||
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(checked.children.length > 0 &&
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existsOne(test, checked.children))));
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}
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/**
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* Search and array of nodes and its children for elements passing a test function.
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*
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* Same as `find`, but limited to elements and with less options, leading to reduced complexity.
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*
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* @category Querying
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* @param test Function to test nodes on.
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* @param nodes Array of nodes to search.
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* @returns All nodes passing `test`.
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*/
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export function findAll(test, nodes) {
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var _a;
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const result = [];
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const stack = nodes.filter(isTag);
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let elem;
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while ((elem = stack.shift())) {
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const children = (_a = elem.children) === null || _a === void 0 ? void 0 : _a.filter(isTag);
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if (children && children.length > 0) {
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stack.unshift(...children);
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}
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if (test(elem))
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result.push(elem);
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}
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return result;
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}
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//# sourceMappingURL=querying.js.map
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